To 500 cm 3 of water, 3.0 × 10 –3 kg of acetic acid is added. If 23% of acetic acid is dissociated, what will be the depression in freezing point? k f and density of water are 1.86 K kgmole –1 and 0.997 g cm –3 respectively
Text Solution
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Weight of water = 500 × 0.997 = 498.5 g
No. of moles of acetic acid = 
= 
= 0.05
Since 498.5 g of water has 0.05 moles of CH 3 COOH
1000 g of water has = 
= 0.1
Determination of van`t Hoff factor, i
CH 3 COOH — → CH 3 COO – + H +
No. of moles at start 1 0 0
No. of moles at equb. 1 – 0.23 0.23 0.23
Δ T f = (1 – 0.23 + 0.23 + 0.23) × 1.86 × 0.1 = 0.228K.
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